Return evenly spaced integers.
start (int, default 0) – Initializer.
step (int, default 1) – Step.
Iterator.
AsyncIterator[int]
Examples
>>> [num async for num in acount(start=23, step=4)] [23, 27, 31, 35, 39, 43, 47, ...]
See also
itertools.count()
Because asyncio.gather() is not enough!
API Reference