aioplus.ahead

aioplus.ahead(aiterable, /, *, n)

Return the first n items of aiterable.

Parameters:

• aiterable (AsyncIterable[T]) – Iterable.

• n (int) – Limit.

Returns:

Iterator.

Return type:

AsyncIterator[T]

Examples

>>> aiterable = arange(23)
>>> [num async for num in ahead(aiterable, n=4)]
[0, 1, 2, 3]

See also

itertools.islice()